What is the flow rate of a canal with an upper opening of 1.4 meters and a bottom of 0.7 meters, and a height of 0.7 meters?

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How wide and high is the channel required for a water flow rate of 1.0.5 cubic meters per second?

The flow rate is related to the flow velocity and cross-sectional area. Cross sectional area=(1+1.5) x1.2 ÷ 2=1.5 (square meters). If the cross-sectional area remains unchanged and the flow velocity=1 meter/second, the flow rate=flow velocity x cross-sectional area=1x1.5=1.5 (cubic meters/He Hongs). The flow rate=3 meters/second, the flow rate=flow velocity x cross-sectional area=3x1.5=4.5 (cubic meters/s)

2. How should the potential energy generated by water in the canal be calculated, teachers? Seeking advice

Let the water flow and land volume in Shuiqiao Qingqu be Q (m ³/s)=1000Q (kg/s), and the water drop be the wide sail h (m); So the potential energy of water is A=1000 Qh joules per second.

3. What is the flow rate of a canal with an upper mouth of 1.4 meters, a bottom of 0.7 meters, and a height of 0.7 meters?

Section area=(upper front and bottom cautious cavity+lower bottom) × height/2=(1.4+0.7) × 0.7/2=2.1 × 0.7/silver stare 2=1.47/2=0.735 square meters Flow rate=fluid velocity × section area. Therefore, as long as the fluid velocity is input into the above formula, it is OK

4. Calculation of weir flow rate

The calculation of weir flow rate is based on specific formulas, where key parameters include H0 (weir head, equal to H plus the square of inlet velocity v0 divided by 2g), flow coefficient m, side contraction coefficient ε, and submergence coefficient σ. The value of m is affected by the inlet size and δ/H of the weir.Tongzhou Zhaoxin often obtains specific empirical formulas for thin-walled weirs, practical cross-section weirs, and wide crest weirs thr

ough experiments. M0 takes into account the influence of near velocity head. The coefficient of lateral contraction ε is related to the size of the diversion canal and weir, and is experimentally determined. When there is no lateral contraction, the value of ε is 1. The submergence coefficient σ is generally determined based on experimental data of thin-walled weirs, practical cross-section weirs, and wide crest weirs, and is related to H0. When flowing in a free weir, σ is equal to 1. The gravitational acceleration g is a fundamental physical constant. Thin walled weir, as the main tool for flow measurement, usually measures the water head H at a distance of more than three times the upstream water head from the weir wall. For a rectangular mouth with no side contraction free thin-walled weir, the flow formula is proportional to the square of Q and H to the power of 1.4, with the formula Q=1.4H ^ 2.5. The flow formula for a weir with a right angled triangle mouth is different, but the applicable simplification condition is that H1 (upstream head) is at least twice H, and the width of the weir mouth B is greater than 3 to 4 times H. Extended information on the slow flow of open channels over obstacles in the channel caused by buildings. Obstacles are called weirs. In engineering, obstacles include dams, bridges, culverts, overflow equipment, etc., which raise the upstream water level and have a lateral contraction and bottom constraint effect on the weir flow. The rapid flow of open channels over obstacles produces hydraulic phenomena different from weir flow. When passing through the side contraction section, a shock wave occurs. Weir flow mainly studies the relationship between the flow rate Q of water flowing through

How wide and high is the channel required for a water flow rate of 1.0.5 cubic meters per second?

2. How should the potential energy generated by water in the canal be calculated, teachers? Seeking advice

3. What is the flow rate of a canal with an upper mouth of 1.4 meters, a bottom of 0.7 meters, and a height of 0.7 meters?

4. Calculation of weir flow rate

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